How do you solve and write the following in interval notation: #-2x<3-x<=8#?

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Answer 1 · 2017-03-28T19:40:18

#x in ]-3;+oo[#

Let's write and solve the equivalent:

#-2x<3-x and 3-x<=8#

#2x-x> -3 and x>=3-8#

#x > -3 and x>=-5#

that's

#x> -3#

or, in interval notation:

#x in ]-3;+oo[#