How do you solve and write the following in interval notation: $-2x<3-x<=8$ ?

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Answer 1 · 2017-03-28T19:40:18

$x in ]-3;+oo[$

Let's write and solve the equivalent:

$-2x<3-x and 3-x<=8$

$2x-x> -3 and x>=3-8$

$x > -3 and x>=-5$

that's

$x> -3$

or, in interval notation:

$x in ]-3;+oo[$

How do you solve and write the following in interval notation: -2x<3-x<=8-2x<3-x<=8?