How do you solve $\frac{1}{2} x + \frac{3}{4} = \frac{1}{6}$ $1/2x+3/4=1/6$ by clearing the fractions?

Question

How do you solve $\frac{1}{2} x + \frac{3}{4} = \frac{1}{6}$ $1/2x+3/4=1/6$ by clearing the fractions?

2 Answers

Impact of this question

2452 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-05T02:16:27

$x = - \frac{7}{6}$ $x=-7/6$

Explanation:

First subtract $\frac{3}{4}$ $3/4$ from both sides giving you,

$\frac{x}{2} = \frac{1}{6} - \frac{3}{4}$ $x/2=1/6-3/4$

Find common denominator,

$\frac{x}{2} = \frac{2}{12} - \frac{9}{12}$ $x/2=2/12-9/12$

Simplify,

$\frac{x}{2} = - \frac{7}{12}$ $x/2=-7/12$

Multiply both sides by 2,

$x = 2 \cdot (- \frac{7}{12}) = - \frac{14}{12}$ $x=2*(-7/12)=-14/12$

Reduce for the final answer of,

$x = - \frac{7}{6}$ $x=-7/6$

Answer 2 · 2017-04-05T02:18:31

Multiply all the terms by the least common denominator.

Explanation:

The LCM of 2,4,and 6 is 12

Multiplying all of the terms by 12 results in

$12 \times 1 \frac{x}{2} + 12 \times \frac{3}{4} = 12 \times \frac{1}{6}$ $12 xx 1x/2 + 12 xx 3/4 = 12 xx 1/6$ This gives
h
$6 x + 9 = 2$ $6x + 9 = 2$ subtract 9 from both sides gives

$6 x + 9 - 9 = 2 - 9$ $6x + 9-9 = 2 -9$ which results in

$6 x = - 7$ $6x = -7$ divide both sides by 6

$6 \frac{x}{6} = - \frac{7}{6}$ $6x/6 = -7 /6$

$x = - \frac{7}{6}$ $x = - 7/6$

Science

Math

Humanities

... and beyond

How do you solve $\frac{1}{2} x + \frac{3}{4} = \frac{1}{6}$ $1/2x+3/4=1/6$ by clearing the fractions?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 12x+34=161/2x+3/4=1/6 by clearing the fractions?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you solve $\frac{1}{2} x + \frac{3}{4} = \frac{1}{6}$ $1/2x+3/4=1/6$ by clearing the fractions?