How do you write the point slope form of an equation for a lint that passes through (-2, 4) with m=-3?

1 Answer
Apr 10, 2017

y=3x2

Explanation:

Use the generl point-slope equatio of, y=mx+b

Where m=slope and b=y-intercept

Given that m=3 the equation of the line now looks like y=3x+b

Given P(2,4), subsitute the x and y coordinates into the equation and solve for b,

4=32+b
4=6+b
b=2

Therefore the equation of the line with a slope of 3 that passes through the point (2,4) is,

y=3x2

graph{-3x-2 [-10, 10, -5, 5]}