How do you write the point slope form of an equation for a lint that passes through (-2, 4) with m=-3?

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Answer 1 · 2017-04-10T16:22:59

#y=-3x-2#

Use the generl point-slope equatio of, #y=mx+b#

Where #m=#slope and #b=#y-intercept

Given that #m=-3# the equation of the line now looks like #y=-3x+b#

Given #P(-2,4)#, subsitute the #x# and #y# coordinates into the equation and solve for #b#,

#4=-3*-2+b#
#4=6+b#
#b=-2#

Therefore the equation of the line with a slope of #-3# that passes through the point #(-2,4)# is,

#y=-3x-2#

graph{-3x-2 [-10, 10, -5, 5]}