How do you solve $- 8 v + 4 (v - 2) = - 32$ $-8v + 4( v - 2) = - 32$ ?

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How do you solve $- 8 v + 4 (v - 2) = - 32$ $-8v + 4( v - 2) = - 32$ ?

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Answer 1 · 2017-04-13T00:54:25

$v = 6$ $v=6$

Explanation:

Multiply $4$ $4$ through the brackets,

$- 8 v + 4 v - 8 = - 32$ $-8v+4v-8=-32$

Collect like terms,

$- 4 v = - 24$ $-4v=-24$

Divide both sides by $- 4$ $-4$ ,

$v = 6$ $v=6$

Answer 2 · 2017-04-13T01:10:32

$v = 6$ $v=6$

See the process in the explanation.

Explanation:

Solve:

$- 8 v + 4 (v - 2) = - 32$ $-8v+4(v-2)=-32$

Expand.

$- 8 v + 4 v - 8 = - 32$ $-8v+4v-8=-32$

Add $8$ $8$ to both sides of the equation.

$-8v+4v-color(red)cancel(color(black)(8))+color(red)cancel(color(black)(8))=-32+8$

Simplify.

$-4v=-24$

Divide both sides by $-4$ .

$color(red)cancel(color(black)(-4v))/color(red)cancel(color(black)(-4))=color(red)cancel(color(black)(-24))^color(blue)6/color(red)cancel(color(black)(-4)^color(blue)1$

Simplify.

$v=6$

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How do you solve $- 8 v + 4 (v - 2) = - 32$ $-8v + 4( v - 2) = - 32$ ?

2 Answers

Explanation:

Explanation:

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How do you solve -8v + 4( v - 2) = - 32−8v+4(v−2)=−32-8v + 4( v - 2) = - 32?

2 Answers

Explanation:

Explanation:

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How do you solve $- 8 v + 4 (v - 2) = - 32$ $-8v + 4( v - 2) = - 32$ ?