What is the equation of a line that goes through #(4, 0)# and #(-7,0 )#?

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Answer 1 · 2017-04-13T01:22:21

#y=0#

Use the slope-point equation #y=mx+b#

Given two points #P_1(4,0)# and #P_2(-7,0)# to solve for the slope or #m#,

#m=(deltaY)/(deltaX)# or #(Y_2-Y_1)/(X_2-X_1)#

Doing so,

#m=(0-0)/(4--7)#

#m=0#

Since their is no slope, the line is just going to be horizontal, the equation will look like #y=0#