What is the equation of a line that goes through $(4, 0)$ $(4, 0)$ and $(- 7, 0)$ $(-7,0 )$ ?

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Answer 1 · 2017-04-13T01:22:21

$y = 0$ $y=0$

Use the slope-point equation $y = m x + b$ $y=mx+b$

Given two points $P_{1} (4, 0)$ $P_1(4,0)$ and $P_{2} (- 7, 0)$ $P_2(-7,0)$ to solve for the slope or $m$ $m$ ,

$m = \frac{δ Y}{δ X}$ $m=(deltaY)/(deltaX)$ or $\frac{Y_{2} - Y_{1}}{X_{2} - X_{1}}$ $(Y_2-Y_1)/(X_2-X_1)$

Doing so,

$m = \frac{0 - 0}{4 - - 7}$ $m=(0-0)/(4--7)$

$m = 0$ $m=0$

Since their is no slope, the line is just going to be horizontal, the equation will look like $y = 0$ $y=0$

What is the equation of a line that goes through (4,0)(4, 0) and (−7,0)(-7,0 )?