Question #b3240
1 Answer
Apr 19, 2017
8.7227 MeV
Explanation:
1 proton = 1.00727638 u
1 neutron = 1.00866492 u
For Ti, 22 protons and 26 neutrons exist:
22 p = 22.1601
26 n = 26.2253
Ti nucleus = 48.3854
You are provided relative mass of 48Ti = 47.9359 amu
The mass defect:
48.3854 (minus)
47.9359
0.4495 u
and as 1 amu = 931.46 MeV
Then mass defect = 418.69 MeV
Per nucleon (48) this amounts to 8.7227 MeV
