How do you write an equation in slope-intercept form for a line with points (4,7) and (8,9)?

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How do you write an equation in slope-intercept form for a line with points (4,7) and (8,9)?

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Answer 1 · 2017-04-21T07:09:59

$y = \frac{1}{2} x + 5$ $y=1/2x+5$

Explanation:

slope intercept form is $y = m x + c$ $y=mx+c$
Start off by finding the slope $m$ $m$
The formula for finding $m$ $m$ is $m = \frac{y_{1} - y_{2}}{x_{1} - x_{2}}$ $m=(y_1-y_2)/(x_1-x_2)$
So $m = \frac{9 - 7}{8 - 4}$ $m=(9-7)/(8-4)$
$m = \frac{2}{4} = \frac{1}{2}$ $m=2/4=1/2$
Now you have $y = \frac{1}{2} x + c$ $y=1/2x+c$
Substitute any one of those points. I am going with $(4, 7)$ $(4, 7)$
So you have $7 = \frac{1}{2} (4) + c$ $7=1/2(4)+c$
$7 = 2 + c$ $7=2+c$
$c = 5$ $c=5$
So your equation is $y = \frac{1}{2} x + 5$ $y=1/2x+5$

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How do you write an equation in slope-intercept form for a line with points (4,7) and (8,9)?

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