How do you find the equations for the normal line to x^2+y^2=20x2+y2=20 through (2,4)?
2 Answers
Apr 23, 2017
Explanation:
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Apr 23, 2017
The equation is
Explanation:
The derivative of this relation is given by
2x + 2y(dy/dx) = 02x+2y(dydx)=0
2y(dy/dx) = -2x2y(dydx)=−2x
dy/dx= -x/ydydx=−xy
The slope of the tangent line is
m_"tangent" = -2/4 = -1/2mtangent=−24=−12
Therefore, the slope of the normal line is
y - 4 = 2(x - 2)y−4=2(x−2)
y- 4= 2x - 4y−4=2x−4
y = 2xy=2x , as obtained in the other answer
Hopefully this helps!