How do you simplify $\frac{- 2 h^{5} - 10 h^{2}}{8 h^{6}}$ $(-2h^5 - 10h^2 )/(8h^6)$ ?

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Answer 1 · 2017-04-26T13:42:03

$= - \frac{1}{4} h - \frac{5}{4 h^{4}}$ $=-1/4h-5/(4h^4)$

Separate the equation
$\frac{- 2 h^{5}}{8 h^{6}} - \frac{10 h^{2}}{8 h^{6}}$ $(-2h^5)/(8h^6)-(10h^2)/(8h^6)$
Separate numbers from variables
$- \frac{2}{8} \frac{h^{5}}{h^{6}} - \frac{10}{8} \frac{h^{2}}{h^{6}}$ $-2/8(h^5)/h^6 -10/8(h^2)/h^6$
Divide. Remember to minus the indices from each other when dividing
$- \frac{1}{4} h^{5 - 6} - \frac{5}{4} h^{2 - 6}$ $-1/4h^(5-6)-5/4h^(2-6$
Simplify
$- \frac{1}{4} h^{1} - \frac{5}{4} h^{- 4}$ $-1/4h^1-5/4h^-4$
$= - \frac{1}{4} h - \frac{5}{4 h^{4}}$ $=-1/4h-5/(4h^4)$

Answer 2 · 2017-04-26T14:07:04

$\frac{(- h^{3} - 5)}{4 h^{4}}$ $((-h^3-5))/(4h^4)$

$\frac{- 2 h^{5} - 10 h^{2}}{8 h^{6}}$ $(-2h^5-10h^2)/(8h^6)$

$:.=(2h^2(-h^3-5))/(8h^6)$

$:.=((-h^3-5))/(4h^(6-2))$

$:.=((-h^3-5))/(4h^4)$

How do you simplify (-2h^5 - 10h^2 )/(8h^6)−2h5−10h28h6(-2h^5 - 10h^2 )/(8h^6)?