Question

How do you graph `f(x)=(1/2)^x -3` by plotting points?

Answer 1

Pick values for `x` that are easy to solve

Explanation:

So we can choose the following `x` values:
`x=-3,-2,-1,0,1,2`

Plugging in the values we get the following
`f(-3)=\frac{2^3}{1^3}-3=2^3-3=8-3=5`
`f(-2)=\frac{2^2}{1^2}-3=2^2-3=4-3=1`
`f(-1)=\frac{2^1}{1^1}-3=2^1-3=2-3=-1`
`f(0)=\frac{1^0}{2^0}-3=1-3=-2`
`f(1)=\frac{1^1}{2^1}-3=\frac{1}{2}-3=-\frac{5}{2}`
`f(2)=\frac{1^2}{2^2}-3=\frac{1}{4}-3=-\frac{11}{4}`

You can plug in the points `(-3,5),(-2,1),(-1,-1),(0,-2),(1,-2.5),(2,-2.75)` to get
graph{(1/2)^x-3 [-14.85, 10.46, -3.99, 8.67]}