How do you evaluate 2\sqrt { 15} ( 3+ \sqrt { 5} )? Algebra Radicals and Geometry Connections Addition and Subtraction of Radicals 1 Answer Manikandan S. May 5, 2017 2sqrt(15)(3+sqrt(5)) = 6sqrt(15)+2sqrt(75) =6sqrt(5\times 3)+2sqrt(25\times 3) = 6sqrt(5)sqrt(3)+10sqrt(3) =sqrt(3)(6sqrt(5)+10) Now substitute values for sqrt(5) and sqrt(3). = 1.732(6\times2.236+10) =1.732\times23.416 =40.556 upto 3rd decimal precision Answer link Related questions How do you add and subtract radicals? How is a radical considered a "like term"? How do you simplify 4\sqrt{3}+2\sqrt{12}? How do you add 3""^3sqrt(2)+5""^3sqrt(16)? How do you subtract \sqrt{8x^3}-4x\sqrt{98x}? How do you combine the radical \sqrt{6}-\sqrt{27}+2\sqrt{54}+3\sqrt{48}? How do you simplify ""^3sqrt{\frac{16x^5}{135y^4}}? What is sqrt(50)-sqrt(18)? How do you add 3sqrt2+4sqrt2? What is the square root of 50 + the square root of 8? See all questions in Addition and Subtraction of Radicals Impact of this question 2560 views around the world You can reuse this answer Creative Commons License