Question

How do you solve and graph `5x+7<=32`?

Answer 1

`x<=5`

Explanation:

First we have
`5x+7<=32`
So we subtract 7 from both sides,
`5x<=25`
And then we divide both sides by 5,
`x<=5`

To graph this on a TI calculator,

Press [y=]
Press [`x,T,theta,n`]
Now press [2nd] and then press [math]
Select the inequality you want, in this case the `<=`
Press enter
Then you type 5

Finally press graph!

So you will see a straight line at `y=1` from `-oo<` `x<=5` and `y=0` from `5<` `x< oo`.
The 1 indicates that the inequality is true and 0 indicates that the inequality is false. Just like how in computer language 1 is true and 0 is false.

Hope this helps :3