How do you write a rule for the nth term of the arithmetic sequence and then find $a_{10}$ $a_10$ for $- 25, - 29, - 33, - 37, - 41$ $-25, -29, -33, -37, -41$ ?

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How do you write a rule for the nth term of the arithmetic sequence and then find $a_{10}$ $a_10$ for $- 25, - 29, - 33, - 37, - 41$ $-25, -29, -33, -37, -41$ ?

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Answer 1 · 2017-05-12T07:11:53

nth term = $- 4 n - 21$ $-4n-21$
10th term = -61

Explanation:

nth term = $a + (n - 1) d$ $a+(n-1)d$
where a = first term of the sequence and d is the constant added or subtracted between successive terms

Here we will substitute a with -25 and d with -4
nth term = $- 25 + (n - 1) - 4$ $-25+(n-1)-4$
= $- 25 + (- 4 n + 4)$ $-25+(-4n+4)$
= $- 25 - 4 n + 4$ $-25-4n+4$
= $- 4 n - 21$ $-4n-21$
10th term = $- 4 (10) - 21$ $-4(10)-21$
= $- 40 - 21$ $-40-21$
= $- 61$ $-61$

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How do you write a rule for the nth term of the arithmetic sequence and then find $a_{10}$ $a_10$ for $- 25, - 29, - 33, - 37, - 41$ $-25, -29, -33, -37, -41$ ?

1 Answer

Explanation:

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How do you write a rule for the nth term of the arithmetic sequence and then find a10a_10 for −25,−29,−33,−37,−41-25, -29, -33, -37, -41?

1 Answer

Explanation:

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How do you write a rule for the nth term of the arithmetic sequence and then find $a_{10}$ $a_10$ for $- 25, - 29, - 33, - 37, - 41$ $-25, -29, -33, -37, -41$ ?