How do you find the domain of $sqrt(x^2+2x-24)$ ?

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Answer 1 · 2017-05-24T14:29:44

the domain is: $]-oo,-6]uu[4,+oo[$

You cannot have negative values under a square root, then it must be:

$x^2+2x-24>=0$

The zeros of the polynomial $x^2+2x-24$ are

$x=-1+-sqrt(1+24)=-1+-5$

that are $x=-6$ and $x=4$

then the domain is:

$]-oo,-6]uu[4,+oo[$

How do you find the domain of sqrt(x^2+2x-24) sqrt(x^2+2x-24)?