Question

Question #19d6f

Answer 1

5.46x`10^22` atoms of Chlorine
1.56g Chloral Hydrate will contain 1g Cl
500 moles of Carbon weighs 6 Kg

Explanation:

We're going to be using this formula a lot for these questions;
Number of moles = `(Mass)/(Molar Mass)`

Number of molecules in a mole = 6.023x`10^23`

Molar Mass (`C_2H_3Cl_3O_2`) = 165.4g
Number of moles of Chloral Hydrate = Mass/Molar Mass
= 0.0302.... moles.
Number of molecules of Chloral Hydrate = 6.023x`10^23` x 0.0302... = 1.821...x`10^22`
3 atoms of chlorine per molecule of chloral hydrate.
Therefore, number of atoms of chlorine = 1.821...x`10^22` x 3 = 5.46386453x`10^22` = 5.46x`10^22`

Number of moles of Chlorine atoms in 1g = 1/35.45 = 0.0282... moles
One molecule of chloral hydrate contains three chlorine atoms, therefore 1/3 of 0.0282... moles of chloral hydrate molecules are needed.
Number of moles of Chloral Hydrate needed = `(0.0282...)/3` = 9.4029...x`10^-3`
Mass = Number of moles x Molar Mass = 9.4029...x`10^-3` x 165.4 = 1.55524...g = 1.56g

Mass of 500 moles of Carbon = 500 x 12 = 6000g = 6 Kg