How do you solve the inequality 2<=abs(4-x)<72|4x|<7 and write your answer in interval notation?

1 Answer
Jun 2, 2017

-3 < x <= 23<x2 OR 6<=x<116x<11

Explanation:

First, recall the rules of absolute values in inequality expressions.

Absolute value is less than something rule
If abs(A) < B|A|<B, that's the same as saying -B < A < BB<A<B

Absolute value is greater than something rule
If B<=abs(A)B|A|, that's the same as saying either B<=ABA or A<=-BAB

The inequality we are given can be broken into two parts.

First part: Less than rule
abs(4-x)<7|4x|<7

Applying the "less than rule" gives
-7<4-x<77<4x<7

Subtract 44 from all three sides
-11 < -x < 311<x<3

Divide by -11 and flip the inequality signs
-3 < x < 113<x<11

Second part: Greater than rule
2<=abs(4-x)2|4x|

Applying the "greater than rule" gives
Either 2<=4-x24x or 4-x<=-24x2

Solving both for xx gives

Either x<=2x2 or x>=6x6

Finally, combine all solutions into one

The solution: -3 < x < 113<x<11 gives the most-negative and most-positive outside boundaries.

The solution: Either x<=2x2 or x>=6x6 gives the inner boundaries.

ANSWER: -3 < x <= 23<x2 OR 6<=x<116x<11

Here is what the graph would look like:
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