Question

Question #b7bb9

Answer 1

The answer is 20.

Explanation:

The `d/dx` of the original function is 2x, using the power rule `nx^(n-1)` where n is our exponent. The derivative of -2 is zero the `d/dx` of a constant is always zero. Now we evaluate the `d/dx` at 10, so 2(10) = 20.

Answer 2

Answer: `20`

Explanation:

Find derivative of `f(x)=x^2-2` at `x=10`

First we need to find the derivative of `f(x)` by using the exponent rule which states that `d/(dx)x^n=nx^(n-1)` and the constant rule which states that `d/(dx)c=0` for constant `c`. So:
`f'(x)=2x`

Now to find `f'(10)` we plug `x=10` into the derivative function:
`f'(10)=2*10=20`

Therefore the derivative of `f(x)=x^2-2` at `x=10` is `20`.