A box with an initial speed of $2 m/s$ is moving up a ramp. The ramp has a kinetic friction coefficient of $1/2$ and an incline of $(2 pi )/3$ . How far along the ramp will the box go?

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Answer 1 · 2017-07-04T21:53:51

0.331m (3sf)

Resolving perpendicular to the slope:
R=mgcos $((2pi)/3)$
R= $(-mg)/2$

F= $mu$ R

F= $(-mg)/4$

Resolving parallel to the slope:
0 - (F + mgsin $((2pi)/3)$ ) = ma (mass cancels)

Using suvat:
s = $(v^2-u^2)/(2a)$
s = 0.331m

A box with an initial speed of 2 m/s2 m/s is moving up a ramp. The ramp has a kinetic friction coefficient of 1/2 1/2 and an incline of (2 pi )/3 (2 pi )/3 . How far along the ramp will the box go?