Question #53d1f

Question

1481 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-15T13:06:44

the element $-12$ is in the solution of the given inequality

We will verify the inequality for each term by substituting it in x, then

$color(red)(x=18)->2/cancel3*cancel18^6+3<-2*18-7->15<-43$ is not true

$color(red)(x=6)->2/cancel3*cancel6^2+3<-2*6-7->7<-19$ is not true

$color(red)(x=-3)->2/cancel3*cancel(-3)^(-1)+3<-2*(-3)-7->1<-1$ is not true

$color(red)(x=-12)->2/cancel3*cancel(-12)^(-4)+3<-2*(-12)-7->-5<17$ is true,

Then the element $-12$ is in the solution of the given inequality.

On the other hand, if we solve the inequality, we will get:

$x<-15/4$

All the elements in A except $-12$ are not in the solution