How do you graph #f(x)=3-x^2# and identify the x intercepts, vertex?

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1 Answer
Robert W.
Jul 26, 2017

Use the standard graph of #y=x^2# but upside down #(y=-x^2)# and then shift it up 3 units.

Explanation:

To find the #x# intercepts, make #f(x)=0# so #x^2=3#. Taking the square root of both sides gives #x=+-sqrt3#.

The vertex of the graph will be at #(0,3)# because the graph hasn't been translated left or right so is still symmetrical about the y-axis.

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