For the function y=3x+2, how do you find the set of coordinates with x-values 1 and 3?

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Answer 1 · 2017-08-09T11:50:34

The coordinates are $: (1, 5)$ $: (1,5)$ $&$ $&$ $(3, 11) .$ $(3,11).$

Function $y = 3 x + 2$ $y = 3x+2$

For $x = 1,$ $x = 1,$

$\Rightarrow y = 3 \cdot 1 + 2$ $=> y= 3*1+2$

$\Rightarrow y = 3 + 2$ $=> y=3+2$

$\Rightarrow y = 5$ $=> y=5$

So the first coordinate is $(1, 5) .$ $(1,5).$

For $x = 3,$ $x=3,$

$\Rightarrow y = 3 \cdot 3 + 2$ $=> y=3*3+2$

$\Rightarrow y = 9 + 2$ $=> y=9+2$

$\Rightarrow y = 11$ $=> y=11$

So the second coordinate is $(3, 11) .$ $(3,11).$

So, the coordinates are $: (1, 5)$ $: (1,5)$ $&$ $&$ $(3, 11) .$ $(3,11).$