Question

Question #f1315

Answer 1

`lambda=6000` m
if talking about light

Explanation:

I'm assuming we are talking about light, so the equation that is used is `c=flambda`, which is speed of light (c) is the product of frequency (f) times wavelength (`lambda`). Remember that Hz`=sec^-1`. Let's rearrange the equation with respect to wavelength and solve for wavelength.

`lambda=c/f=(3.00*10^8 m/s)/(50000Hz)=(3.00*10^8m/s)/(50000sec^-1)=6000` m

This is assuming you are referring to light.

If you are not talking about light, then the equation will be `lambda=v/50000`, where v is the generic term for velocity.