Question #eeed8

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Question #eeed8

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Answer 1 · 2017-09-05T16:30:59

$312.5 J$ $312.5J$

Explanation:

Firstly I assumed that no energy has been lost in the process. Thus, implying that,

$K . E = G . P . E$ $color(red) (K.E)=color(blue)(G.P.E)$

Where:
1 $K . E$ $color(red)(K.E)$ : Kinetic energy
2 $G . P . E$ $color(blue)(G.P.E)$ : Gravitational Potential energy
Then

$K . E$ $color(red)(K.E)$ = $\frac{1}{2} \cdot m \cdot v^{2}$ $1/2*m*v^2$
$K . E = \frac{1}{2} \cdot 25 \cdot {(5)}^{2}$ $K.E= 1/2*25*(5)^2$
$K . E = 312.5 J$ $K.E=312.5J$

-Then, using the aforementionned assumption, we get,

$G . P . E = 312.5 J$ $color(blue)(G.P.E)=312.5J$

I hope I was useful to help you solve your concern.

Cheers ;).

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Question #eeed8

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