Question

How do you convert `x=y²-6y+11` into polar form?

Answer 1

see below

Explanation:

Use the formulas `x=rcos theta, y=rsin theta` to substitute into the equation.

That is,

`x=y^2 -6y +11`

`rcos theta = r^2 sin^2 theta -6rsin theta +11`

`0=r^2sin^2 theta-6rsin theta-rcos theta +11`