How do you solve and graph $abs((2p-8)/4)>=9$ ?

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Answer 1 · 2017-09-16T11:38:17

$p<=-14 or p>=22$

Let's consider that:

$|f(x)|>=a$ is equivalent to

$f(x)<=-a or f(x)>=a$

Then

let's solve the equivalent form:

$(2p-8)/4<=-9 or (2p-8)/4>=9$

Let's multiply all terms by 4 to eliminate fractions:

$2p-8<=-36 or 2p-8>=36$

let's transfer -8 to the right side and divide all terms by 2:

$2p<=-28 or 2p>=44$

$p<=-14 or p>=22$

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How do you solve and graph abs((2p-8)/4)>=9abs((2p-8)/4)>=9?