How do you find the exact value of #tan^-1 0#?

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Answer 1 · 2017-09-28T02:21:59

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Remember that #tan(theta) = sin(theta)/cos(theta)#

You're looking for some angle #theta# for which #sin(theta)/cos(theta) = 0#

...this occurs whenever #sin(theta) = 0#.

Which happens when #theta = 0, pi, 2pi, # (etc.)

For the inverse trig functions, you use only the first angle in this list.

So therefore, you can deduce that #tan^-1(0) = 0#

GOOD LUCK!