How do you graph y=2cot4x?
1 Answer
Oct 7, 2017
Explanation:
Using
a⋅cot(bx+c)+d ,
where:
a=2 b=4 c=0 d=0 Period
=πb=π4 ... One cycle completes atπ4 Phase shift
=cb=04=0 ...Phew! that means no problemVertical shift
=d=0 ... Again no problem!
At
π8 , (half of the period),y=0
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At
π16 , (half of theπ8 ),y=a=2 At
3π16 , (batweenπ8 and the period),y=−a=−2
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Three points are
→(π16,2),(π8,0),(3π16,−2)
Therefore,
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