How do you simplify #3sin4x + 3sin4x #?

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Answer 1 · 2017-10-09T19:11:12

#6sin4x#

You have two like terms: #sin4x#

#3sin4x +3sin4x = 6sin4x#

Answer 2 · 2017-10-09T19:42:47

Let's see.

To simplify, two formulas of multiple angles are required #rarr#

#(1) sin2x=2sinxcosx#.

#(2) cos2x=cos^2x-sin^2x#.

Now,
#3sin4x+3sin4x#

#=6sin4x#

#=6xx[2xx(sin2x)xx(cos2x)]#

#=12xx[2xx(sinx)xx(cosx)xx(cos^2x-sin^2x)]#

#=24sinxcosx(cosx+sinx)(cosx-sinx)#. (Answer).

Hope it Helps:).