How do you find the domain of g(t)=(t+4)/(t^2-16)g(t)=t+4t216?

1 Answer
Oct 10, 2017

t!=+-4t±4 or t in(-oo,+oo)-{+-4}t(,+){±4} or t in RR-{+-4}

Explanation:

The function is g(x)=(t+4)/(t^2-16

Its written in the form of a fraction. As we know the denominator of a fraction can never be 0, therefore we'll apply a condition to the function.

t^2-16!=0

t^2!=16

t!=sqrt16

Therefore

t!=+-4

So t can be any number except +-4

If you want to write it in interval notation it can be written as:-

t in(-oo,+oo)-{+-4}

             or

tinRR-{+-4}