How do you divide $\frac{- 2 x^{4} + x^{2} + 8 x - 7}{5 x - 2}$ $(-2x^4+x^2+8x-7)/(5x-2)$ ?

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How do you divide $\frac{- 2 x^{4} + x^{2} + 8 x - 7}{5 x - 2}$ $(-2x^4+x^2+8x-7)/(5x-2)$ ?

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Answer 1 · 2017-10-11T13:10:00

$- \frac{2 x^{3}}{5} - \frac{4 x^{2}}{25} + \frac{17 x}{125} + \frac{1034}{625}, r = - \frac{2307}{625}$ $-(2x^3)/5-(4x^2)/25+(17x)/125+1034/625, r=-2307/625$

Explanation:

$- \frac{2 x^{3}}{5} - \frac{4 x^{2}}{25} + \frac{17 x}{125} + \frac{1034}{625}, r = - \frac{2307}{625}$ $" "-(2x^3)/5-(4x^2)/25+(17x)/125+1034/625, r=-2307/625$
$5 x - 2 ∣ - 2 x^{4} + 0 x^{3} + x^{2} + 8 x - 7$ $5x-2|-2x^4+0x^3" "+x^2" "+8x-7$
$- - 2 x^{4} + \frac{4 x^{3}}{5}$ $" "- -2x^4+(4x^3)/5$
$0 - \frac{4 x^{3}}{5}$ $" "0-(4x^3)/5$
$- - \frac{4 x^{3}}{5} + \frac{8 x^{2}}{25}$ $" "- -(4x^3)/5+(8x^2)/25$
$0 + \frac{17 x^{2}}{25}$ $" "0+(17x^2)/25$
$- \frac{17 x^{2}}{25} - \frac{34 x}{125}$ $" "-(17x^2)/25-(34x)/125$
$0 + \frac{1034 x}{125}$ $" "0+(1034x)/125$
$- \frac{1034 x}{125} - \frac{2068}{625}$ $" "-(1034x)/125-2068/625$
$0 - \frac{2307}{625}$ $" "0-2307/625$

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How do you divide $\frac{- 2 x^{4} + x^{2} + 8 x - 7}{5 x - 2}$ $(-2x^4+x^2+8x-7)/(5x-2)$ ?

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Explanation:

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How do you divide $\frac{- 2 x^{4} + x^{2} + 8 x - 7}{5 x - 2}$ $(-2x^4+x^2+8x-7)/(5x-2)$ ?