How do you divide #(-2x^4+x^2+8x-7)/(5x-2)#?

1 Answer
1s2s2p
Oct 11, 2017

#-(2x^3)/5-(4x^2)/25+(17x)/125+1034/625, r=-2307/625#

Explanation:

#" "-(2x^3)/5-(4x^2)/25+(17x)/125+1034/625, r=-2307/625#
#5x-2|-2x^4+0x^3" "+x^2" "+8x-7#
#" "- -2x^4+(4x^3)/5#
#" "0-(4x^3)/5#
#" "- -(4x^3)/5+(8x^2)/25#
#" "0+(17x^2)/25#
#" "-(17x^2)/25-(34x)/125#
#" "0+(1034x)/125#
#" "-(1034x)/125-2068/625#
#" "0-2307/625#

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