Question

What is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 47.3 calories of heat and the temperature rises 15.0°C?

Answer 1

See below.

Explanation:

The equation used to solve for specific heat capacity is this:

`q=s*m*DeltaT` where q heat absorbed or lost, s is the specific heat capacity, m is the mass, and `DeltaT` is the change in temperature `"final temperature"-"initial temperature"`

From what the problem gave us, we can plug in the numbers:

`47.3=s*55.00*15.0`

Simplify:

`47.3=s*825`

Divide by 825 on both sides:

`0.0573=s`

The units of `s` will be in `"cal"/(g*C` for this problem, so `s=0.0573 "cal"/(g*C)`