What is the slope of the line going through (5, -4) and (6, -2)?

2 Answers
Dec 5, 2017

See a solution process below:

Explanation:

The slope can be found by using the formula: #m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#

Where #m# is the slope and (#color(blue)(x_1, y_1)#) and (#color(red)(x_2, y_2)#) are the two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(-2) - color(blue)(-4))/(color(red)(6) - color(blue)(5)) = (color(red)(-2) + color(blue)(4))/(color(red)(6) - color(blue)(5)) = 2/1 = 2#

Use the slope equation
The slope is #m=2#.

Explanation:

#m = ("change in " y)/("change in " x)#

The letter #m# is used to represent the slope.

Call one point #(x_1,y_1)# and the other point #(x_2,y_2)#

Then

#m = (y_2-y_1)/(x_2-x_1)#

So if #(5,-4)# is #(x_1,y_1)# and #(6,-2)# is #(x_2,y_2)#, then The slope equation states

#m = (y_2-y_1)/(x_2-x_1) = (-2-(-4))/(6-5) = 2/1= 2#

The slope equals two.