Question

How do you find the standard form given `x^2-2x-4y-11=0`?

Answer 1

`y=x^2/4-x/2-11/4`

Explanation:

STANDARD FORM: `y=ax^2+bx+c`

Make `x^2-2x-4y-11=0` look like `y=ax^2+bx+c`.

`x^2-2x-4y-11=0` [Add `4` to both sides.]
`x^2-2x-11=4y` [Divide by `4` to isolate y.]
`x^2/4-(2x)/4-11/4=y` [Simplify.]
`x^2/4-x/2-11/4=y`

ANSWER: `y=x^2/4-x/2-11/4`