Question #96660 Physics Forces and Newton's Laws Frictional Forces 1 Answer MattyMatty Dec 14, 2017 F = 12,525 N" (answer C)" Explanation: x = v_0 t + a t^2/2 v = v_0 + a t v = 0 => t = -v_0/a => x = -v_0^2 / (2a) 30^2 / (2a) = -53.5 => a = -8.41 m/s^2 20^2 / (2a) = -23.9 => a = -8.37 m/s^2 10^2 / (2a) = -6.1 => a = -8.20 m/s^2 => a = -8.35 m/s^2 => F = m a = 1,500 * 8.35 = 12,525 N Answer link Related questions Question #d6539 Question #242b7 Question #6bde4 Question #50c79 Question #a2018 Question #f7a62 Question #27931 Question #0b375 Question #d70af Question #dab6f See all questions in Frictional Forces Impact of this question 1597 views around the world You can reuse this answer Creative Commons License