How is the graph of #y=1/3x^2-4# related to the graph of #f(x)=x^2#?

1 Answer
Dec 23, 2017

The lines intersect
#(sqrt(6),6)(-sqrt(6),6)#

Explanation:

f(x) is the expression used for functions. It is another way of showing the y value because it depends on the variable x. The y value is created after the x value is put through the function

Thus

#f(x) = x^2 # is the same as #y = x^2#

Both equation have y as their subjects. This way an inequality can be created.

#x^2=1/3x^2-4#

Make x the subject

#x^2+4=1/3x^2#

#3x^2+12=x^2#

#2x^2 = -12#

#x^2=-6#

#x=+-sqrt(6)#

Once the x coordinate has been found, the y one can be found two. There are two values of x so there are also two coordinates.

#(sqrt(6),6)(-sqrt(6),6)#