A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $7$ , $4$ , and $9$ , respectively. What is the rectangle's area?

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Answer 1 · 2017-12-30T21:28:42

$9sqrt33$

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This is what I am imagining the your problem looks like, based on the information you gave.

First, use the pythagorean theorem to find side B:
$sqrt(7^2-4^2$ = $sqrt(33$

Then find the area of the rectangle:
$9 cdot sqrt(33$ = 9 $sqrt(33$ or $51.7$

A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of 7 7 , 4 4 , and 9 9 , respectively. What is the rectangle's area?