What is the slope of the tangent line of r=(sin^2theta)/(2theta-thetacos2theta) at theta=(pi)/4?

1 Answer
Jan 15, 2018

slope is the derivative value at a given value of theta

Explanation:

dr/dtheta
by quotient rule:
it is
(2sinthetacostheta(2theta -thetacos2theta) - (sin^2theta)(2 - (cos2theta + theta(-sin2theta)*2)))/(2theta - thetacos2theta)^2
now placing the value of theta = pi/4
you can find slope
hope u find it helpful :)