Question

How do you find the antiderivative of `(x-6)^2`?

Answer 1

`1/3x^3-6x^2+36x+C`

Explanation:

Expand and then use power rule.
`(x-6)^2`= `x^2-12x+36`
`int_` `x^2-12x+36` dx = `1/3x^3-6x^2+36x+C`

Remember power rule is `int_` `ax^n` = `(ax^(n+1))/(n+1)`