How do you simplify $- 2 - \frac{2}{3} (3 - 3 x)$ $-2- \frac { 2} { 3} ( 3- 3x )$ ?

Question

1774 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-05T08:20:06

$- 4 + 2 x$ $-4+2x$

$- 2 - \frac{2}{3} (3 - 3 x)$ $-2 - 2/3(3 - 3x)$

Multiply $3$ $3$ and $- 3 x$ $-3x$ by $- \frac{2}{3}$ $-2/3$

$- 2 - 2 + 2 x$ $-2-2+2x$

$- 4 + 2 x$ $-4+2x$

Answer 2 · 2018-02-05T08:20:31

First comes multiplication.....

$-2-2/cancel3xxcancel3-2/cancel3xx-cancel3x$

Which gives

$-2-2+2x$

$-4+2x$

If we take $0$

$-4+2x=0$

$2x=4$

$x=4/2$

$x=2$

How do you simplify -2- \frac { 2} { 3} ( 3- 3x ) −2−23(3−3x)-2- \frac { 2} { 3} ( 3- 3x ) ?