If $2 x + 14$ $2x + 14$ for $- 7 \leq x < - 5, 4$ $-7<=x<-5, 4$ for $- 5 \leq x < 1$ $-5<=x<1$ and $\frac{3}{2} x + \frac{5}{2}$ $3/2x + 5/2$ for $x \geq 1$ $x>=1$ , how do you find $f (- 6)$ $f(-6)$ ?

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If $2 x + 14$ $2x + 14$ for $- 7 \leq x < - 5, 4$ $-7<=x<-5, 4$ for $- 5 \leq x < 1$ $-5<=x<1$ and $\frac{3}{2} x + \frac{5}{2}$ $3/2x + 5/2$ for $x \geq 1$ $x>=1$ , how do you find $f (- 6)$ $f(-6)$ ?

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Answer 1 · 2018-02-28T07:46:49

2

Explanation:

From the question:
$f (x) = 2 x + 14$ $f(x)=2x+14$ for $- 7 \leq x < - 5$ $-7lex<-5$
$g (x) = 4$ $g(x)=4$ for $- 5 \leq x < 1$ $-5lex<1$
$h (x) = \frac{3}{2} x + \frac{5}{2}$ $h(x)=3/2x+5/2$ for $1 \leq x$ $1lex$

When x=-6, only $f (x)$ $f(x)$ is applicable.

Hence,
$f (- 6)$ $f(-6)$
$= 2 (- 6) + 14$ $=2(-6)+14$
$= 2$ $=2$

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If $2 x + 14$ $2x + 14$ for $- 7 \leq x < - 5, 4$ $-7<=x<-5, 4$ for $- 5 \leq x < 1$ $-5<=x<1$ and $\frac{3}{2} x + \frac{5}{2}$ $3/2x + 5/2$ for $x \geq 1$ $x>=1$ , how do you find $f (- 6)$ $f(-6)$ ?

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Explanation:

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Explanation:

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If $2 x + 14$ $2x + 14$ for $- 7 \leq x < - 5, 4$ $-7<=x<-5, 4$ for $- 5 \leq x < 1$ $-5<=x<1$ and $\frac{3}{2} x + \frac{5}{2}$ $3/2x + 5/2$ for $x \geq 1$ $x>=1$ , how do you find $f (- 6)$ $f(-6)$ ?