How do you solve $3 x^{2} = 48$ $3x^2=48$ ?

Question

19183 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-04T18:29:25

$x = \pm 4$ $x=+-4$

We begin by dividing both sides by $3$ $3$ :

$(cancel3x^2)/cancel3=48/3$

$x^2=16$

Take the square root on both sides (and don't forget the negative root):

$sqrt(x^2)=+-sqrt(16)$

$x=+-4$

How do you solve 3x^2=483x2=48 3x^2=48?