How do you evaluate #-( \frac { 1} { 2} ) ^ { 2} + 3+ 2#?

1 Answer
Mar 4, 2018

#19/4#

Explanation:

First, raise the fraction to a power of 2 by raising the numerator and denominator to that power
#1^2/2^2# = #-1/4#

Then add the numbers
#3+2=5#
so we get #-1/4+5#
Now add them
Write all numerators above the common denominator
#-1/4+20/4#

Add the numerator together
= #19/4#