What are the intercepts of $- 17 y - x = 7$ $-17y-x=7$ ?

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Answer 1 · 2018-03-05T08:52:43

$x - intercept = - 7$ $x-"intercept"=-7$

$y - intercept = - \frac{7}{17}$ $y-"intercept"=-7/17$

$- 17 y - x = 7$ $-17y-x=7$

For finding $x$ $x$ -intercept , put $y = 0$ $y=0$ .

$\Rightarrow - 17 (0) - x = 7$ $=> -17(0)-x=7$

$\Rightarrow - x = 7$ $=> -x=7$

$\Rightarrow x = - 7$ $=> x=-7$

We got $x$ $x$ -intercept $= - 7$ $=-7$ .

For finding $y$ $y$ -intercept , put $x = 0$ $x=0$ .

$\Rightarrow - 17 y - (0) = 7$ $=> -17y-(0)=7$

$\Rightarrow - 17 y = 7$ $=> -17y=7$

$\Rightarrow y = - \frac{7}{17}$ $=> y=-7/17$

We got $y$ $y$ -intercept $= - \frac{7}{17}$ $=-7/17$ .

What are the intercepts of −17y−x=7-17y-x=7?