What is the kinetic energy of a $16 kg$ object moving at $4 m/s$ ?

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Answer 1 · 2018-03-09T16:21:27

128 joules

kinetic energy= $frac{1}2 xx mass xx (velocity)^2$
thus, $frac{1}2 xx 16xx16 or 128" joules"$ is the kinetic energy of the body

Answer 2 · 2018-03-10T07:27:33

$128$ joules

The kinetic energy of an object is expressed through the equation:

$"KE"=1/2mv^2$

where $m$ is the mass of the object in kilograms, $v$ is the velocity of the object in meters per second.

We got: $m=16 \ "kg", v=4 \ "m/s"$

So, plugging in the values into the equation, we get

$"KE"=1/2*16 \ "kg"*(4 \ "m/s")^2$

$=8 \ "kg"*16 \ "m"^2"/s"^2$

$=128 \ "kg m"^2 \ "s"^2$

Know that $1 \ "kg m"^2 \ "s"^2=1 \ "J"$ .

So, we got $128 \ "J"$ of kinetic energy, i.e. the object's kinetic energy is $128$ joules.

What is the kinetic energy of a 16 kg16 kg object moving at 4 m/s4 m/s?