How do you find the slope of the line passing through (5,-2) and (-3,-1)?

1 Answer
Nityananda
Mar 10, 2018

-1/8

Explanation:

We know slope of a line passing through the points (x_1,y_1)&(x_2,y_2) is [y_2-y_1]/[x_2-x_1](x1,y1)&(x2,y2)isy2−y1x2−x1

here (x_1,y_1)=(5,-2) & (x_2,y_2)=(-3,-1)(x1,y1)=(5,−2)&(x2,y2)=(−3,−1)

So, slope = [-1-(-2)]/[-3-5]−1−(−2)−3−5

rArr [-1+2]/[-8] = -1/8⇒−1+2−8=−18

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