How do you solve $x^2-8x=-16$ ?

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Answer 1 · 2018-03-12T07:50:50

$x = 4$

$x^2 - 8x = -16$

First, you move all the terms to the left side by adding 16 to both sides
$x^2 - 8x +16 = -16 +16$
$x^2 - 8x + 16 = 0$

Then you factor
$( x - 4 )( x - 4 ) = 0$

Simplify
$( x - 4 )^2$

Solve
$( x - 4 )^2 = 0$
$x = 4$

How do you solve x^2-8x=-16x^2-8x=-16?