How many grams of chromium are needed to react with an excess of $CuSO_4$ to produce 16.2 g Cu?

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Answer 1 · 2018-03-15T14:13:34

its $8.775g$

Write down the equation for this reaction and balance it

$3CuSO_4 + 2Cr = 3Cu +Cr_2(SO_4)_3$
Calculate the amount of moles of copper. We have $16g$ , and its molar mass is $64g$ :

$16/64 = 0.25$

And thus the mole for chromium will be $0.17$

As the ratio suggests $2:3$

Thus $(0.25*2)/ 3 = 0.17$

Use this mole and substitute in the equation $"moles"="mass"/"molar mass"$ to calculate the mass which is $0.17 * 52= 8.775g$

How many grams of chromium are needed to react with an excess of CuSO_4CuSO_4 to produce 16.2 g Cu?