Question

How do you graph: `y = 2^x + 2`?

Answer 1

Look at the explanation for this is a "how" question.

Explanation:

First you have to know how the equation `y=a^x` looks.
It looks like this:
graph{1.5^x [-83.3, 83.35, -41.66, 41.65]}
That is the general shape.

The range of every equation for `y=a^x` is `(0, oo)`
Also the point `(0,1)` exists on every exponential function because `a^0 = 1`
Also there is always a horizontal asymptote at `y=0` unless there is a vertical shift, then it moves up or down.

Now plug in some points
`x=-1, y=0.5`
`x=1, y=2`
`x=2, y=4`

Now you just shift the whole graph up by 2
This makes the horizontal asymptote at `y=2`
graph{2^x+2 [-83.3, 83.35, -41.66, 41.65]}