Question

How do you evaluate `5/6-2/3`?

Answer 1

`1/6`

Explanation:

Both fractions must have the same denominators before you can add the numerators:.

`5/6 -(2xx2)/(3xx2)`

`=5/6 -4/6`

`=1/6`

Answer 2

`1/6`

Explanation:

`"before subtracting the fractions we require them to have"`
`"a "color(blue)"common denominator"`

`"this is achieved by multiplying numerator/denominator"`
`"of "2/3" by 2, thus making the denominator 6"`

`rArr5/6-((2xxcolor(red)(2))/(3xxcolor(red)(2)))`

`=5/6-4/6`

`"now subtract the numerators leaving the denominator"`

`=(5-4)/6=1/6`

Answer 3

Make both numbers have a common denominator of 6, then just subtract to get `1/6`

Explanation:

To subtract the numerators (numbers at the top), find a common denominator (number at the bottom), which in this case I'll use 6, since 6 is a common multiple of both 6 and 3

So to convert `2/3` to `n/6`, where `n` just stands for some number you want to find, multiply both top and bottom by 2

`2/3=(2*2)/(3*2)=4/6`

So you replace `2/3` with `4/6` in that expression

`5/6-2/3=5/6-4/6=(5-4)/6=1/6`

To get the answer `1/6`