How do you evaluate $x + {(y - 1)}^{3}$ $x+(y-1)^3$ if w=6, x=4, y=-2, z=6?

Question

1792 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-20T05:37:11

$- 23$ $-23$

The equation has two variables: $x$ $x$ and $y$ $y$ .
Given the two variables are 4 and -2.

Therefore,
$x + {(y - 1)}^{3}$ $x+(y-1)^3$

$= 4 + {(- 2 - 1)}^{3}$ $=4+(-2-1)^3$

$= 4 + (- 27)$ $=4+(-27)$

$= - 23$ $=-23$

How do you evaluate x+(y−1)3x+(y-1)^3 if w=6, x=4, y=-2, z=6?